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8x^2+14x-17=2x^2-3
We move all terms to the left:
8x^2+14x-17-(2x^2-3)=0
We get rid of parentheses
8x^2-2x^2+14x+3-17=0
We add all the numbers together, and all the variables
6x^2+14x-14=0
a = 6; b = 14; c = -14;
Δ = b2-4ac
Δ = 142-4·6·(-14)
Δ = 532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{532}=\sqrt{4*133}=\sqrt{4}*\sqrt{133}=2\sqrt{133}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{133}}{2*6}=\frac{-14-2\sqrt{133}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{133}}{2*6}=\frac{-14+2\sqrt{133}}{12} $
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